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x^2+6.5x+3=0
a = 1; b = 6.5; c = +3;
Δ = b2-4ac
Δ = 6.52-4·1·3
Δ = 30.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.5)-\sqrt{30.25}}{2*1}=\frac{-6.5-\sqrt{30.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.5)+\sqrt{30.25}}{2*1}=\frac{-6.5+\sqrt{30.25}}{2} $
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